-20+37t-16t^2=0

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Solution for -20+37t-16t^2=0 equation:



-20+37t-16t^2=0
a = -16; b = 37; c = -20;
Δ = b2-4ac
Δ = 372-4·(-16)·(-20)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{89}}{2*-16}=\frac{-37-\sqrt{89}}{-32} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{89}}{2*-16}=\frac{-37+\sqrt{89}}{-32} $

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